Having read two of the explanations of the Monty Hall issue I have
found that neither of them have been bennificial two me in anyway at
all. As far as I am concerned having three doors gives you a 1:3 chance
of winning , however once you eliminate a door you are only left with
two choices , hence each door has a 1:2 chance of having a prize behind
it. I left wondering how many other people are sure that they
understand what was proposed in the lecture and the following
Skywriting. Can somebody please explain to me ( In English ) how to go
about resolving this problem. Betts, Steven.
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